Accept any three numbers and find their squares and cubes.

This is one of the easiest C program. All you have to do is, accept three numbers and display their squares and cubes.

## Tutorial 📺

Watch tutorial and understand how to solve this 😉

## Steps 🪜

### To find squares and cubes of 3 numbers

1. Display a message to the user and accept three numbers. Store these values in three variables n1, n2 and n3. Since, we can display the results directly using printf statements that is why no need to declare extra variables to store the results.
2. Write three printf() statements to display the modulo operation by 2, 3 and 4 respectively. That’s it. 😎

## Flow Chart 🌻

Check how to draw flow chart for this program.

## Code 💻

``````#include <stdio.h>
#include <conio.h>

int main()
{
float n1=0, n2=0, n3=0;
scanf("%f%f%f", &n1, &n2, &n3);
// Square and Cube of n1
printf("\n\nSquare of n1: %0.2f", n1 * n1);
printf("\n\nCube of n1: %0.2f", n1 * n1 * n1);
// Square and Cube of n2
printf("\n\nSquare of n2: %0.2f", n2 * n2);
printf("\n\nCube of n2: %0.2f", n2 * n2 * n2);
// Square and Cube of n3
printf("\n\nSquare of n3: %0.2f", n3 * n3);
printf("\n\nCube of n3: %0.2f", n3 * n3 * n3);
return 0;
}``````

## Example 😍

Let’s assume, the user enters 3 numbers as 2, 4 and 6. As we know, it is displaying results directly through printf statements without any extra variables.

So, first it will display the squares and cubes of 2 i.e. 4 and 8. Next, it will display the squares and cubes of 4 i.e. 16 and 64. Finally, it will display the squares and cubes of 6 i.e. 36 and 216.

The output will be like this:

``````Square of n1: 4

Cube of n1: 8

Square of n2: 16

Cube of n2: 64

Square of n3: 36

Cube of n3: 216``````

This is how you can find squares and cubes of any 3 numbers. 😇